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# QUESTION 1 Convert the following C program into an x86 assembly language program. Make sure to use your Chapter 8

QUESTION 1
Convert the following C++ program into an x86 assembly language program.
Make sure to use your Chapter 8 understanding of advanced functions, parameter passing, and local variables.
Post ONLY your ASM file here to Blackboard when complete.#include
using namespace std;
int IsSemifauxtrifactored(int value)
{
// Return 1 if a numbers factors/divisors from (value – 1) to 1 sum up to half the number value
// Return 0 otherwise
// A number is called semifauxtrifactored if its summed factors/divisors equal half the number itself
// Integer division is used, so remainders on the halving can be lost
// Thats why…
// 9 is a semifauxtrifactored number
// 9 cut in half with integer division is (9 / 2) = 4
// 9
% 8 -> 1
// 9
% 7 -> 2
// 9
% 6 -> 3
// 9
% 5 -> 4
// 9
% 4 -> 1
// 9
% 3 -> 0
FACTOR!
// 9
% 2 -> 1
// 9
% 1 -> 0
FACTOR!
// 9 is a semifauxtrifactored number since its factors (1 + 3) equal half the number (4)
// 6 is a normal number
// 6 cut in half with integer division is (6 / 2) = 3
// 6
% 5 -> 1
// 6
% 4 -> 2
// 6
% 3 -> 0
FACTOR!
// 6
% 2 -> 0
FACTOR!
// 6
% 1 -> 0
FACTOR!
// 6 is a normal number since its factors (1 + 2 + 3) do not equal half the number (3)
}
int main()
{
cout << Enter a value: ;
int value;
cin >> value;
value = IsSemifauxtrifactored(value);
if (value == 1)
{
cout << The number is semifauxtrifactored!;
}
else
{
cout << The number is normal;
}
cout << endl;
system(PAUSE);
}

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